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35k^2-6k-8=0
a = 35; b = -6; c = -8;
Δ = b2-4ac
Δ = -62-4·35·(-8)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-34}{2*35}=\frac{-28}{70} =-2/5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+34}{2*35}=\frac{40}{70} =4/7 $
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